I've been thinking (and searching) about this for days but haven't reached anywhere:
How do you calculate the total power output of an open delta transformer? I don't understand the explanation given in various texts and on websites:
http://yourelectrichome.blogspot.com...f3phase.html
The √3 E _{L}I _{L} formula was for closed delta because in a closed delta, we calculate the power delivered by one winding as E _{L}*I _{phase} which becomes E _{L}*(I _{L}/√3) since phase current=I _{L}/√3, and then multiply by three.
But why are we using this formula for open delta?
And btw, in the conductor attached to the point where the two windings are joined together, would the line current be √3I _{phase}?
