IEC 60287 Current Capacity of Cables - Rated Current 

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This note looks at the formulae used to calculate the rated current capacity of a cable in line with IEC 60287 "Calculation of the continuous current rating of cables (100% load factor)".   Before you continue reading this note, if you have not done so already we would suggest first reading our IEC 60287 introduction note:

      IEC 60287 Current Capacity of Cables - An Introduction

In the previous note we looked at the approach taken by the standard to the sizing of cables and illustrated this with an example.  We then looked at one method of applying the standard and identified resources enabling the calculation of all the various parameters involved.   In the note we are going to put everything together and reveal the necessary equations for actually calculating the cable maximum current rating.

The image illustrates  the thermal model for a cable. 



Heat is generated within the cable by various mechanisms -  conductor I2R loss, dielectric loss, sheath loss, armour loss and direct solar radiation.  Some or all of this heat is dissipated through the cable insulation, bedding, serving and into the surrounding medium.  The rate of heat flow is related to the temperature difference across the cable and affected by the ambient temperature, temperature rises due to other cables and any critical temperature rise of the soil above ambient.

In thermal equilibrium, when all these factors have balanced and the temperature of the conductor is the maximum allowable for the insulation; we have the maximum rated current for the cable.  It can probably be appreciated by now, that in typical real life situations, this can be quite a complicated calculation.

Note: rated current capacity found by the method assumes that the cable is fully loaded for 100% of it's operation time.  For cables which have varying or cyclic loads, the current rating could possibly be increased.

Tip: the thermal model is worth remembering as enables us to intuitively understand how a cable is likely to behave in conditions which are not normally encountered.  For example, if a cable is run along a refrigerated gas pipe, we can hazard that this will reduce the ΔΘ and hence the cable will be able to carry more current. 

Change in temperature across a material is equal to the heat input multiplied by the thermal resistance of the material.  In terms of the thermal model and for a simple a.c. cable, the heat balance equation is given by (a list of symbols is given at the end of the note):


Within the standard this above is used to derive the equations for current rating.  It is simplified for d.c. cables by eliminating any a.c. only effects and modified for partial drying of soil and solar radiation where appropriate.

Rated Current of Cables

The standard gives the following equations for the calculation of the cable current rating (for all alternating current voltages and direct current up to 5 kV):

Buried cables where drying out of the soil does not occur or cables in air

AC cables


DC cables


Buried cables where partial drying-out of the soil occurs

AC cables

I= [ Δθ W d [0.5 T 1 +n( T 2 + T 3 +v T 4 )]+(v1)Δ θ X R[ T 1 +n(1+ λ 1 ) T 2 +n(1+ λ 1 + λ 2 )( T 3 +v T 4 )] ] 0.5


DC cables

I= [ Δθ+( v1 )Δ θ X R ' [ T 1 +n T 2 +n( T 3 +v T 4 ) ] ] 0.5

Buried cables where drying-out of the soil is to be avoided

AC cables

I= [ Δ θ x n W d T 4 nR T 4 ( 1+ λ 1 + λ 2 ) ] 0.5

DC cables


Cables directly exposed to solar radiation

AC cables


DC cables


Note: when calculating a cable where some drying of the soil may occur, it is also necessary to perform the calculation for no drying out of soil and take the worse case (lower) rating.

The calculation of each element needs some explanation and these have been split across several notes (with each note dealing with one topic).  For details, please refer to the first note in this series, which lists the other related notes. 

List of Symbols

n - number of load carrying conductors
v - ratio of thermal resistivity of dry and moist soils

I - rated conductor current, A
R - a.c. resistance of the conductor per unit length,  Ω/m
R' - d.c. resistance of the conductor per unit length, Ω/m   

T1 - thermal resistance per core between conductor and sheath, K.m/W
T2 - thermal resistance between sheath and armour, K.m/W
T3 - thermal resistance of external serving, K.m/W
T4 - thermal resistance of surrounding medium, K.m/W
T4* - external thermal resistance (free air) adjusted for solar radiation, K.m/W

De* - cable diameter over insulation, m
H - intensity of solar radiation, W/m2
Wd - dielectric loss per units length, W/m

λ1 - ratio of losses in metal sheath to total losses in all conductors
λ2 - ratio of losses in armouring to total losses in all conductors
σ - absorption coefficient of solar radiation for cable surface

Θ - maximum conductor operating temperature, °C 
Θa - ambient temperature, °C 
ΔΘ - temperature difference (Θ-Θa), K
ΔΘx - critical temperature of soil, °C

Steven McFadyen's avatar Steven McFadyen

Steven has over twenty five years experience working on some of the largest construction projects. He has a deep technical understanding of electrical engineering and is keen to share this knowledge. About the author

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comments powered by Disqus

  1.'s avatar says:
    2/22/2013 10:23 AM

    I dont know how i can thank you for the great information's you provide,and its really appreciated..
    once more thank you very much and keep on.

  2. Paul Mercier's avatar Paul Mercier says:
    10/9/2013 10:13 AM

    Just to notify you, but correct me if I'm wrong. I need to use your calculation but there is a mistake with the factorisation of the denominator in the formula for buried cables where drying-out of the soil occur for AC cable. (It looks logical, otherwise we would have been a squared resistance in the denominator).

    • Steven's avatar Steven says:
      10/9/2013 4:30 PM

      Thanks for the feedback. I've modified the drying out equations slightly. Let me know if you have still think something is wrong.

    • Paul Mercier's avatar Paul Mercier says:
      11/5/2013 2:53 PM

      Just another thing I've just noticed (still easy to figure out because of unexpected results) in the section "Buried cables where drying-out of the soil is to be avoided", AC part, in the numerator, it should be a subtraction instead of an addition.
      To let a positive comment, I find your website very helpful. Thank you.

    • 11/6/2013 4:30 AM

      Paul, please feel free to keep pointing out problems. Feedback is one way I can improve the articles.
      For anyone referring to BS IEC 60287:2006, please be aware that the formula given for AC cables where drying out of soil is to be avoided, contains the above error. IEC 60287, itself does have the correct equation.

  3. Notes's avatar Notes says:
    10/13/2013 2:14 PM

    Trackback from Notes

    When sizing cables, the heat generated  by losses within any sheath or armour need to be evaluated. When significant, it becomes a factor to be considered in the sizing of cables. This note looks at how to obtain the necessary loss factors for use within... ...

  4. ARIJIT's avatar ARIJIT says:
    10/23/2013 4:03 PM

    This formulas really helpful, but my question is what is the limit of overcurrent carrying capacity of cable?

    • 10/24/2013 7:40 AM

      Arjijit, I'm not to sure exactly what you are asking. The equations give a safe steady state rated current for a cable. If you exceed this value of current, you could be affecting the life of the cable. The more you exceed the greater the effect.

      My view is that you should used the equations to select the cable based on your anticipated current rating. You then select an approppropriate protective device to isolated the cable should you exceed this value.

      If you have a load current which is genuinely varying, you could use IEC 60853 "Calculation of the cyclic and emergency current rating of cables. Part 1: Cyclic rating factor for cables up to and including 18/30(36) kV".

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